Thread: Spellsurge
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Old 05/16/07, 1:02 PM   #47
Kazanir
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So, let T be the time between procs, and C be the average time between casts. That means that T = 50 + (1/.15) * C. That means that I, the individual mana regained, is I = 100 / [ 50 + (1/.15) * C ] mana per second or 500 / T mp5 equivalent. Thus M, total mana regained (with P being the number of mana users in your party) is:

M = 500P / ( 50 + 20C/3 ) mp5

Thus, assuming a full party of casters:

Cast Time | Mana per 5
----------+-----------
     1.5s | 41.7 mp5
     2.0s | 39.5 mp5
     2.5s | 37.5 mp5
     3.0s | 35.7 mp5
     3.5s | 34.1 mp5
Edit:

Originally Posted by Erongg View Post
Extend that to infinity and take the weighted average.
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[13:07] <Kazanir> Vontre was responsible for Black Mesa
[13:08] <Vontre> Is Black Mesa some Half-Life thing?
 
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