Originally Posted by Groggan
Did I?
What I'm doing is taking the base damage of a shot, and multiplying it by
[(Crit%*CritMod) + (hit%-crit%)]
So that distributes to (with X representing base damage)
(Crit%*CritMod*X) + (hit%-crit%)*X
or with 100% chance to hit
(Crit%*CritMod*X) + (1-crit%)*X
Is that not correct? I wana say that's how Cheeky does it in his spreadsheet (and I think he verified that part for me), but I could be wrong too :P |
That distributes for a one roll system (crits are not hits, hits are not crits). IF it uses a two roll system (crits are hits, not all hits are crits), critical strikes are the product of hit and crit. This would look like:
[(hit%-hit%*crit%)+hit%*(crit%*CritMod)]*DamageFromShot
So the sum of hits and crits is equal to the hit%, which may be less than 100% of all attacks (it doesn't account for misses, but with 100% to hit it is the same as your last formula, which we would expect). Anyway, you could simplify that equation but I think that form is most demonstrative of my point. This is why I asked; again, I haven't confirmed it's a two roll special / one roll auto system yet, but that's the mathematical line of reasoning with which I approached it.